(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5,求m+n的值
问题描述:
(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5,求m+n的值
答
(a^m+1b^n+2)(a^2n-1b^2n)=a^5b^5?
[a^(m+1)b^(n+2)][(^(2n-1)b^(2n)]=a^5b^5
=a^(m+2n)b^(3n+2)
3n+2=5,n=1
m+2n=5,m=3
m+n=4