已知x²+y²+2xy-2x-2y+1=0,则(x+y)^2010=

问题描述:

已知x²+y²+2xy-2x-2y+1=0,则(x+y)^2010=

x2+y2+2xy-2x-2y+1=0
(x+y)^2-2(x+y)+1=0
(x+y-1)^2=0
x+y=1
(x+y)^2010=1^2010=1