已知x^2-4x+3=(x-1)^2+m(x-1)+n,求m、n的值
问题描述：
已知x^2-4x+3=(x-1)^2+m(x-1)+n,求m、n的值
答
x^2-4x+3=(x-1)^2+m(x-1)+n
x²-4x+3
=x²-2x+1+mx-m+n
=x²-(2-m)x+(1-m+n)
-4=-(2-m),m=-2,
1-m+n=3,1-(-2)+n=3,n=0;