求值sin(π/2)*sin(π/3)+2cos(-π/2)-根号3*tan(π/3)
问题描述：
求值sin(π/2)*sin(π/3)+2cos(-π/2)-根号3*tan(π/3)
答
sin(π/2)*sin(π/3)+2cos(-π/2)-√3*tan(π/3)
=sin(π/3)+0-√3*tan(π/3)
=√3-√3*√3
=√3-3答案是二分之根号三-根号三吧sin(π/3)=二分之根号三。是吧？？sin(π/3)=二分之根号三。不好意思 sin(π/2)*sin(π/3)+2cos(-π/2)-√3*tan(π/3)=sin(π/3)+0-√3*tan(π/3)=√3/2-√3*√3=√3/2-3