已知du=2xydx+x²dy,求原函数u(x,y)
问题描述：
已知du=2xydx+x²dy,求原函数u(x,y)
答
du=2xydx+x²dy
=ydx^2 + x^2dy
= d(x^2y)
(u,xy) = x^2y + C