1/In(x+1)的导数是什么
问题描述:
1/In(x+1)的导数是什么
答
[1/In(x+1)]'
=-1/ln²(x+1)*[ln(x+1)]'
=-1/ln²(x+1)*1/(x+1)
=-1/[(x+1)ln²(x+1)]