√a^5+2a^3·b^2+ab^4 (x≥0,y≥0)
问题描述:
√a^5+2a^3·b^2+ab^4 (x≥0,y≥0)
这是二次根式怎么做
还有一题
√12x^2y+24x^2·y^3
答
√(a^5+2a^3·b^2+ab^4)
=√[a(a^4+2a^2b^2+b^4)
=√[a(a^2+b^2)^2]
=(a^2+b^2)√a
√(12x^2y+24x^2·y^3)
=√[12x^2y(1+2y^2)
= 2x√[3y(1+2y^2)]