如果6x平方-4x4-+3=7,求式子3x平方-2x+10的值

分类: 作业答案 • 2022-01-10 20:54:01

问题描述：

答

6X^2-7xy-3y^2-x+7y-2
=6x^2-(7y+1)x-(3y^2-7y+2)
=6x^2-(7y+1)x-(y-2)(3y-1)
=[2x-(3y-1)][3x+(y-2)]
=(2x-3y+1)(3x+y-2)