(x-3/x+3+6x/x²-9)÷1/x²-9

问题描述:

(x-3/x+3+6x/x²-9)÷1/x²-9
化简就行

[(x-3)/(x+3)+6x/(x²-9)]÷1/(x²-9 )= {(x-3)²/[(x+3)(x-3)]+6x/(x²-9)]÷1/(x²-9 )={(x-3)²+6x]/(x²-9)}÷1/(x²-9 )=(x-3)²+6x=x²-6x+9+6x=x²+9