已知x/2=y/3=z/4,求(xy+yz+zx)/x²+y²+z²的值

问题描述:

已知x/2=y/3=z/4,求(xy+yz+zx)/x²+y²+z²的值

x/2=y/3=z/4=m,则x=2m,y=3m,z=4m.原式=(6m²+12m²+8m²)/(4m²+9m²+16m²)=26/29