化简[sin(π/2-α)cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π+α)
问题描述:
化简[sin(π/2-α)cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π+α)
答
原式=(cosαsinα)/(-cosα)-(sinαsinα)/sinα
=-sinα-sinα
=-2sinα