解不等式：－1/2≤sinx≤√3/2
问题描述：
解不等式：－1/2≤sinx≤√3/2
答
先求在区间[-π/2,3π/2]上的解集.数形结合可知,此时x∈[-π/6,π/3]∪[2π/3,7π/6].∴由函数周期性可知,x∈[2kπ-π/6,2kπ+π/3]∪[2kπ+2π/3,2kπ+7π/6].k∈Z.
解不等式：－1/2≤sinx≤√3/2
先求在区间[-π/2,3π/2]上的解集.数形结合可知,此时x∈[-π/6,π/3]∪[2π/3,7π/6].∴由函数周期性可知,x∈[2kπ-π/6,2kπ+π/3]∪[2kπ+2π/3,2kπ+7π/6].k∈Z.