化简:【1/(tanα/2)-tan(α/2)】(1+tan^2α)(角α的平方)

问题描述:

化简:【1/(tanα/2)-tan(α/2)】(1+tan^2α)(角α的平方)

已经知道 tan 2A = 2tanA/[1 - (tanA)^2]1/(tanα/2)-tan(α/2) =[ 1 - tan(α/2)^2] / tan(α/2)= 2tan(a/2)/[tan a * tan(α/2) = 2/tan a = 2cos a/sin a1+tan^2α = 1 + sin^2 α/cos^2 α = 1/cos^2 α...