sin25派/6+cos25派/3-tan25派/4
问题描述:
sin25派/6+cos25派/3-tan25派/4
答
原式=sin[4π+(π/6)]+cos[8π+(π/3)]-tan[6π+(π/4)]
=sin(π/6)+cos(π/3)-tan(π/4)
=(1/2)+(1/2)-1
=0