把1/x-2,1/(x-1)(x+2),2/(x-1)的2次方通分
问题描述:
把1/x-2,1/(x-1)(x+2),2/(x-1)的2次方通分
答
1/(x-2)=(x-1)²(x+2)/[(x-2)(x-1)²(x+2)]
1/(x-1)(x+2)=(x-2)(x-1)/[(x-2)(x-1)²(x+2)]
2/(x-1)²=2(x+2)(x-2)/[(x-2)(x-1)²(x+2)]