x-3y+2z=1 2x+2y-3z=-10 4x-8y+5z=6

问题描述:

x-3y+2z=1 2x+2y-3z=-10 4x-8y+5z=6
解三元一次

x-3y+2z=1 (1)
2x+2y-3z=-10 (2)
4x-8y+5z=6 (3)
(1)×2+(2)×3
8x-5z=-28 (4)
(2)×4+(3)
12x-7z=-34 (5)
(5)×5-(4)×7
60x-56x=-170+196
4x=26
所以
x=13/2
z=)12x+34)/7=16
y=(x+2z-1)/3=25/2