化简[sin﹙2π+α﹚]/[cos﹙﹣π-α﹚cot﹙π/2-α﹚]=__

问题描述:

化简[sin﹙2π+α﹚]/[cos﹙﹣π-α﹚cot﹙π/2-α﹚]=__

[sin﹙2π+α﹚]/[cos﹙﹣π-α﹚cot﹙π/2-α﹚]=sin(α)/【(-cosα)*sinα/cosα】=-1

[sin﹙2π+α﹚]/[cos﹙﹣π-α﹚cot﹙π/2-α﹚]
=sinα/(-cosα*tanα)
=-tanα/tanα
=-1