化简[sin﹙2π+α﹚]/[cos﹙﹣π-α﹚cot﹙π/2-α﹚]=__
问题描述:
化简[sin﹙2π+α﹚]/[cos﹙﹣π-α﹚cot﹙π/2-α﹚]=__
答
[sin﹙2π+α﹚]/[cos﹙﹣π-α﹚cot﹙π/2-α﹚]=sin(α)/【(-cosα)*sinα/cosα】=-1
答
[sin﹙2π+α﹚]/[cos﹙﹣π-α﹚cot﹙π/2-α﹚]
=sinα/(-cosα*tanα)
=-tanα/tanα
=-1