(c²-a²-b²)²-4a²b²(因式分解)
问题描述:
(c²-a²-b²)²-4a²b²(因式分解)
答
(c²-a²-b²)²-4a²b²=(c²-a²-b²+2ab)(c²-a²-b²-2ab)=[c²-(a-b)²]c²-(a+b)²]=(c-a+b)(c+a-b)(c+a+b)(c-a-b)
(c²-a²-b²)²-4a²b²(因式分解)
(c²-a²-b²)²-4a²b²=(c²-a²-b²+2ab)(c²-a²-b²-2ab)=[c²-(a-b)²]c²-(a+b)²]=(c-a+b)(c+a-b)(c+a+b)(c-a-b)