用处等变换法求矩阵的逆
问题描述:
用处等变换法求矩阵的逆
1 1 1
2 -1 1
1 2 0
答
(A,E) =1 1 1 1 0 02 -1 1 0 1 01 2 0 0 0 1r2-2r1,r3-r11 1 1 1 0 00 -3 -1 -2 1 00 1 -1 -1 0 1r1-r3,r2+3r31 0 2 2 0 -10 0 -4 -5 1 30 1 -1 -1 0 1r2*(-1/4),r1-2r2,r3+r21 0 0 -1/2 1/2 1/20 0 1 5/4 -1/4 -3/4...