2x+2Y+2z=12 2x+2y+4z=14 x+3y+z=10

问题描述:

2x+2Y+2z=12 2x+2y+4z=14 x+3y+z=10

2x+2y+2z=12-----①
2x+2y+4z=14-----②
4x+3y+z=10-------③
②-①
2z=2
z=1
分别将z=1带入②③
2x+2y=10---------④
4x+3y=9-----------⑤
④*2-⑤
y=11
x=-6那个是x+3y+z=10.....2x+2y+2z=12-----①2x+2y+4z=14-----②x+3y+z=10-------③②-①2z=2z=1③*2-②4y-2z=64y=8y=2x=3