因式分解题一道,x方-3ax+2a方-ab-b方
问题描述:
因式分解题一道,x方-3ax+2a方-ab-b方
答
设x²-3ax+2a²-ab-b²=0,则解得:x=½[3a±﹙a+2b﹚],∴x1=2a+b,x2=a-b,∴原式=[x-﹙2a+b﹚][x-﹙a-b﹚]=﹙x-2a-b﹚﹙x-a+b﹚
因式分解题一道,x方-3ax+2a方-ab-b方
设x²-3ax+2a²-ab-b²=0,则解得:x=½[3a±﹙a+2b﹚],∴x1=2a+b,x2=a-b,∴原式=[x-﹙2a+b﹚][x-﹙a-b﹚]=﹙x-2a-b﹚﹙x-a+b﹚