已知tana/2=2求tan(a+π/4)2、（6sina+cosa）/3sina-2cosa的值

已知tana/2=2求tan(a+π/4)
tana=2tana/2/(1-tan^2a/2)
=4/(1-4)
=-4/3
tan(a+π/4)=(tana+tanπ/4)/(1-tanatanπ/4)
=(-4/3+1)/(1+4/3)
=-1/7
2、sina=2tana/2/(1+tan^2a/2)
=4/(1+4)
=4/5
cosa=(1-tan^2a/2)/(1+tan^2a/2)
=(1-4)/(1+4)
=-3/5
所以有：
(6sina+cosa）/(3sina-2cosa)
=(24/5-3/5)/(12/5+6/5)
=21/18
=7/6

1.∵tan(a/2)=2∴tana=[2tan(a/2)]/{1-[tan(a/2)]^2}=(2×2)/(1-2^2)=-4/3∴tan(a+π/4)=[tana+tan(π/4)]/[1-tana×tan(π/4)]=(-4/3+1)/(1+4/3)=-1/72.原式=(6sina/cosa+cosa/cosa)/(3sina/cosa-2cosa/cosa)=(6tan...