计算不出现终止子的概率
问题描述：
计算不出现终止子的概率
Consider a nucleotide sequence that is generated randomly with equal probabilities for each of the four bases.What is the probablity of observing a sequence of 20 codons that are not stop codoons?
答
纯数学问题.
密码子一共64种,其中三种是终止密码子.所以某个密码子不是终止密码子的概率是61/64
现在20个密码子都不是种子密码子,所以是61/64的20次方,约等于28.3%