(x^5-6x³+7x²-7x+3)÷(x³-2x+1)
问题描述:
(x^5-6x³+7x²-7x+3)÷(x³-2x+1)
答
x^5-6x^3+7x^2-7x+3=(x^2-4)(x^3-2x+1)+6x^2-15x+7,所以原始=x^2-4+(6x^2-15x+7)|x^3-2x+1
(x^5-6x³+7x²-7x+3)÷(x³-2x+1)
x^5-6x^3+7x^2-7x+3=(x^2-4)(x^3-2x+1)+6x^2-15x+7,所以原始=x^2-4+(6x^2-15x+7)|x^3-2x+1