已知121(x-1)^2=36,y^3 +8=0,求
问题描述：
已知121(x-1)^2=36,y^3 +8=0,求
(1)x-y的值
(2)x^y的值
答
121(x-1)^2=36
11（x-1)=6
x-1=6/11
x=17/11
y^3 +8=0
y^3=-8
y=-2
x-y=17/11+2=39/11
x+y=17/11-2=5/11