先化简,再求值 (2ab)(-2ab)+(3ab)(3ab+2),期中a-3,b=2

问题描述:

先化简,再求值 (2ab)(-2ab)+(3ab)(3ab+2),期中a-3,b=2

(2ab)(-2ab)+(3ab)(3ab+2)
=-4a*a*b*b+9a*a*b*b+6a*b
=5a*a*b*b+6ab
=ab(5ab+6)
a=3,b=2
那么 ab(5ab+6)=3*2*(5*3*2+6)
=216