已知向量a=(sinθ,1),b=(1,cosθ),-π/2
问题描述:
已知向量a=(sinθ,1),b=(1,cosθ),-π/2
数学人气:413 ℃时间:2020-04-11 03:12:36
优质解答
|a+b|²=(sinθ+1)²+(1+cosθ)²=sin²θ+2sinθ+1+cos²θ+2cosθ+1
=3+2(sinθ+cosθ)=3+2√2sin( θ+π/4)
|a+b|≤√(3+2√2)=1+√2
=3+2(sinθ+cosθ)=3+2√2sin( θ+π/4)
|a+b|≤√(3+2√2)=1+√2
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答
|a+b|²=(sinθ+1)²+(1+cosθ)²=sin²θ+2sinθ+1+cos²θ+2cosθ+1
=3+2(sinθ+cosθ)=3+2√2sin( θ+π/4)
|a+b|≤√(3+2√2)=1+√2