计算(a-2/(a²+2a)-a-1/a²+4a+4)÷(1-(6)/a+2)
问题描述:
计算(a-2/(a²+2a)-a-1/a²+4a+4)÷(1-(6)/a+2)
答
=[(a-2)/a(a+2)-(a-1)/(a+2)²]×(a+2)/(a-4)
=[(a²-4)-(a²-a)]/a(a+2)²×(a+2)/(a-4)
=1/a(a+2)