(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
问题描述：
(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
要简便
答
只需要把式子乘一个(2^2-1)除一个(2^2-1)就可以了(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)＝(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)/(2^2-1)=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)/(2^2-1)=.=(2^64-1)/(2^2-...