(1+2)(1+2^2/1)(1+2^4/1)(1+2^8/1)+2^16/1
问题描述:
(1+2)(1+2^2/1)(1+2^4/1)(1+2^8/1)+2^16/1
答
(1+2)(1+2^2/1)(1+2^4/1)(1+2^8/1)+2^16/1
=(1+2)(1+2^2/1)(1+2^4/1)(1+2^8/1)(1-2^8/1)/(1-2^8/1)+2^16/1
=(1+2)(1+2^2/1)(1+2^4/1)(1-2^4/1)/(1-2^8/1)+2^16/1
=(1+2)(1+2^2/1)(1-2^2/1)/(1-2^8/1)+2^16/1
=(1+2)(1-2)/(1-2^8/1)+2^16/1
=-3/(1-2^8/1)+2^16/1