(x+2y)^2(x^2-2xy+4y^2)^2=

问题描述:

(x+2y)^2(x^2-2xy+4y^2)^2=

(x+2y)^2(x^2-2xy+4y^2)^2
=(x+2y)²(x-2y)²
=(x²-4y²)²
=x^4-8x²y²+16y^4那(x^2-2xy+4y^2)^2算出不是应该是【(x-2y)²】^2吗(x+2y)^2(x^2-2xy+4y^2)^2=(x+2y)²(x-2y)^4是滴?能清楚点吗?(x+2y)^2(x^2-2xy+4y^2)^2=(x+2y)²【(x-2y)²】^2=(x+2y)²(x-2y)^4