①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^
问题描述:
①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^
答
①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^
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