(x+1)(x+2)/6x最小值是多少,
问题描述:
(x+1)(x+2)/6x最小值是多少,
答
(x+1)(x+2)/6x=(x^2+3x+2)/6x
=(x+2/x)/6+1/2
x>0才有最小值√2/3+1/2 x=√2