已知tanα=2,sin²α-3sinαcosα+1=
问题描述：
已知tanα=2,sin²α-3sinαcosα+1=
答
(sinα)^2-3sinαcosα+1=[(sinα)^2-3sinαcosα+(sinα)^2+(cosα)^2]/[(sinα)^2+(cosα)^2]=[2(sinα)^2-3sinαcosα+(cosα)^2]/[(sinα)^2+(cosα)^2]分子分母同除(cosα)^2=[2(tanα)^2-3tanα+1]/[(tan...