若实数X,Y满足X^2+3Y^2-12Y+12=0,则Y的值是?
问题描述:
若实数X,Y满足X^2+3Y^2-12Y+12=0,则Y的值是?
答
X^2+3Y^2-12Y+12=0 X^2+3(Y^2-4Y+4)=0 X^2+3(Y-2)^2=0 则X=0 Y=2
若实数X,Y满足X^2+3Y^2-12Y+12=0,则Y的值是?
X^2+3Y^2-12Y+12=0 X^2+3(Y^2-4Y+4)=0 X^2+3(Y-2)^2=0 则X=0 Y=2