函数y=sinπ/2*sin[π/2(x-1)]的最小正周期是
问题描述:
函数y=sinπ/2*sin[π/2(x-1)]的最小正周期是
答
y=sinπ/2*sin[π/2(x-1)]=sin[π/2(x-1)]
T=2π/(π/2)=4