函数y=sinπ/2*sin[π/2(x-1)]的最小正周期是

问题描述:

函数y=sinπ/2*sin[π/2(x-1)]的最小正周期是

y=sinπ/2*sin[π/2(x-1)]=sin[π/2(x-1)]
T=2π/(π/2)=4