g(x)=∫(上标-x,下标0) sin(t^2)dt 求g'(x)
问题描述:
g(x)=∫(上标-x,下标0) sin(t^2)dt 求g'(x)
答
g'(x)
= d/dx ∫[0,-x] sin(t²) dt
= -sin[(-x)²]
= -sin(x²)