已知x∈【0,π/2】求函数g(x)=cos(π/12-x)-cos(5π/12+x)的值域

问题描述:

已知x∈【0,π/2】求函数g(x)=cos(π/12-x)-cos(5π/12+x)的值域

g(x)=cos(π/12-x)-cos(5π/12+x)=sin(5π/12+x)-cos(5π/12+x)=√2*[√2/2*sin(5π/12+x)-√2/2*cos(5π/12+x)]=√2*sin(5π/12+x-π/4)=√2*sin(x+π/6)因为x∈[0,π/2],所以x+π/6∈[π/6,2π/3],所以sin(x+π/6)...