求解方程x^2/3+48/x^2=10(x/3-4/x)
问题描述：
求解方程x^2/3+48/x^2=10(x/3-4/x)
答
设t=x/3-4/x则t²=(x/3-4/x)²=x²/9-8/3+16/x²t²+8/3=x²/9+16/x²两边乘以3,得3t²+8=x²/3+48/x²则方程可以写为3t²+8=10t3t²-10t+8=0(3t-4)(t-2)=0t=2或4/...