求不定积分∫1/(x^2+4)dx求高手解题要步骤谢谢
问题描述：
求不定积分∫1/(x^2+4)dx求高手解题要步骤谢谢
答
∫1/(x^2+4)dx
=1/4∫1/[1+(x/2)²]dx
=1/2∫1/[1+(x/2)²]d(x/2)
=1/2arctanx/2+c