解方程组0.5x+0.8y=4.7 0.6x+1.2y=6.

问题描述:

解方程组0.5x+0.8y=4.7 0.6x+1.2y=6.

5x+8y=47 (1)
6x+12y=66 (2)
x+2y=11 (2)' 解出:x=11-2y 代入(1)得到:5(11-2y)+8y=47
55-10y+8y=47
2y=8
y=4
x=11-2*4=3
即:x=3
y=4
验证:将x=3,y=4 代入(1)(2)正确无误!