(a-b+c-d)(a+b-c-d)=[(a-d)-_][(a-d)+_]

问题描述:

(a-b+c-d)(a+b-c-d)=[(a-d)-______][(a-d)+______]

因为a-b+c-d=a-d-b+c=(a-d)-(b-c),
a+b-c-d=(a-d)+(b-c),
所以(a-b+c-d)(a+b-c-d)=[(a-da-d)+(b-c)],
故填(b-c);(b-c).