计算,要有过程1/(5a-20)+5/(a²-9a+20)
问题描述:
计算,要有过程1/(5a-20)+5/(a²-9a+20)
答
1/(5a-20)+5/(a²-9a+20)
=1/[5(a-4)]+5/[(a-4)(a-5)]
=[(a-b)+25]/[5(a-4)(a-5)]
=(a-b+25)/(5a²-45a+100)
很高兴为您解答,【the 1900】团队为您答题.
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