计算,要有过程1/(5a-20)+5/(a²-9a+20)

问题描述:

计算,要有过程1/(5a-20)+5/(a²-9a+20)

1/(5a-20)+5/(a²-9a+20)
=1/[5(a-4)]+5/[(a-4)(a-5)]
=[(a-b)+25]/[5(a-4)(a-5)]
=(a-b+25)/(5a²-45a+100)
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请点击下面的【选为满意回答】按钮.��һ��[(a-b)+25]/[5(a-4)(a-5)]��ʲô��˼公分母是:5(a-4)(a-5)通分的过程!