[(Xˉy)^2+(x+y)(xˉy)]/x,其中x=1,y=2分之1
问题描述:
[(Xˉy)^2+(x+y)(xˉy)]/x,其中x=1,y=2分之1
答
[(Xˉy)^2+(x+y)(xˉy)]/x
=[x²-2xy+y²+x²-y²]/x
=[2x²-2xy]/x
=2x-2y
=2×1-2×2分之1
=2-1
=1