在三角形ABC中,若b/c=3/5,则(sinB+2sinC)/sinC=
问题描述:
在三角形ABC中,若b/c=3/5,则(sinB+2sinC)/sinC=
如题
答
根据正弦定理得:b/sinB=c/sinC
即:sinB/sinC=b/c=3/5
(sinB+2sinC)/sinC
=sinB/sinc+2sinC/sinC
=3/5+2
=13/5