解方程:13/(x-4)-10/(x-3)=4/(x-5)-1/(x-1) 不能漏

问题描述:

解方程:13/(x-4)-10/(x-3)=4/(x-5)-1/(x-1) 不能漏
解方程:13/(x-4)-10/(x-3)=4/(x-5)-1/(x-1)
不要网上抄,我不会才问的

合并得(13(x-3)-10(x-4)/(x*x-7x+12)=(4(x-1)-(x-5))/(x*x-6x+5)
去里面的括号并和并得(3x+1)/(x*x-7x+12)=(3x+1)/(x*x-6x+5)
交叉相乘并约分得x*x-7x+12=x*x-6x+5
x=7