m∧logaN=n∧logaM

问题描述:

m∧logaN=n∧logaM

ogaN=n∧loga

令x=M^logaN
则取以a为底的对数
loga(x)
=loga[M^logaN]
=logaN*logaM
=logaM*logaN
=loga[N^logaM]
所以x=N^logaM
所以M^logaN=N^logaM