已知x/2=y/3=z/4 求:(3x-4y+6z) / (5x+8y-2z)

问题描述:

已知x/2=y/3=z/4 求:(3x-4y+6z) / (5x+8y-2z)
已知:x/2=y/3=z/4 求:(3x-4y+6z) / (5x+8y-2z)

令x/2=y/3=z/4=k那么x=2k y=3k z=4k
代入:(3x-4y+6z) / (5x+8y-2z)=(6k-12k+24k)/(10k+24k-8k)=18k/26k=9/13