正整数x、y、z满足x&3-y&3-z&3=3xyz,x²=0(y+z),则xy+yz+xz=()
问题描述:
正整数x、y、z满足x&3-y&3-z&3=3xyz,x²=0(y+z),则xy+yz+xz=()
答
x&3-y&3-z&3=3xyz
x²=0(y+z),x=0
3(y+z)=0
因为想,x,y ,z正整数所以y=0
z=0
xy+yz+xz=(0)