lim(x→0)(ln(1+2x)/(e^x-1))
问题描述:
lim(x→0)(ln(1+2x)/(e^x-1))
答
0/0型极限,用L'Hospital法则
lim(x→0)(ln(1+2x)/(e^x-1))
=lim(x→0)((ln(1+2x))'/(e^x-1)')
=lim(x→0)(2/(1+2x)/e^x)
=2